2(2a-4)^2+11(2a-4)+12=0

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Solution for 2(2a-4)^2+11(2a-4)+12=0 equation:



2(2a-4)^2+11(2a-4)+12=0
We multiply parentheses
2(2a-4)^2+22a-44+12=0
We add all the numbers together, and all the variables
22a+2(2a-4)^2-32=0
We move all terms containing a to the left, all other terms to the right
22a+2(2a-4)^2=32

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